dedeCMS怎样返回上一级目录 获取当前上一级栏目名称及链接

{dede:channel type='top' row='80'}

<li><a href="[field:typeurl/]">[field:typename/]</a></li>

{/dede:channel}

部分换成

{dede:channelartlist }

<div class="样式1">

{dede:type}<li class="clearfix"><a class="f_l">[field:typename/]</a></li>{/dede:type}

<span>

{dede:channel type='son' noself='yes'}

<a href="[field:typeurl/]" title="[field:typename/]">[field:typename/]</a>|{/dede:channel}

</span>

</div>

{/dede:channelartlist}

这是子栏目调用：

{dede:channel type='son'}

<li><a href="[field:typeurl/]">[field:typename]</a></li>

{/dede:channel}

{dede:field name='typeid' runphp='yes'}

global $dsql;

/获取当前栏目id/

$typeid = @me;

$query = "SELECT reid FROM dede_arctype where id = $typeid";

$rs = $dsql->GetOne($query);

$reid = $rs['reid'];//获取到栏目的上级栏目

/获取上级栏目id/

$query2 = "SELECT FROM dede_arctype where id = $reid";

$typerow = $dsql->GetOne($query2);

/输出上级栏目信息/

$typename = $typerow['typename'];

$link = GetTypeUrl($typerow['typeid'],MfTypedir($typerow['typedir']),$typerow['isdefault'],$typerow['defaultname'],$typerow['ispart'],$typerow['namerule2'],$typerow['moresite'],$typerow['siteurl'],$typerow['sitepath']);

@me = "<a href='/{$link}'>$typename</a>";

{/dede:field}

后台dedecms系统配置参数里面的站点根网址设置成这样就行了，再或者是这样，添加栏目的时候外链填写，文件保存目录是下面所示

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